1/1x3+1/3x5+1/5x7+...1/2001x2003中用了什么法则,将和式中的各分数转化为两个数之得
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/07/13 17:37:07
1/1x3+1/3x5+1/5x7+...1/2001x2003中用了什么法则,将和式中的各分数转化为两个数之得
1/1x3+1/3x5+1/5x7+...1/2001x2003
=(1/1-1/3)/2+(1/3-1/5)/2+(1/5-1/7)/2+...+(1/2001-1/2003)/2
=(1/1-1/3+1/3-1/5+1/5-1/7+...+1/2001-1/2003)/2
=(1-1/2003)/2
=2002/2003除以2
=1001/2003
再问: 孩子啊,我问的是用了什么法则!
再答: 用了积化和差,合并同类项法则
=(1/1-1/3)/2+(1/3-1/5)/2+(1/5-1/7)/2+...+(1/2001-1/2003)/2
=(1/1-1/3+1/3-1/5+1/5-1/7+...+1/2001-1/2003)/2
=(1-1/2003)/2
=2002/2003除以2
=1001/2003
再问: 孩子啊,我问的是用了什么法则!
再答: 用了积化和差,合并同类项法则
1/(1x3)+1/(3x5)+1/(5x7)+.+1/(2011x2013) 等于什么
1/1X3+1/3X5+1/5X7...1/17X19+1/19X21=
1/1x3+1/3x5+1/5x7.1/2009x2010+1/2011x2013
1/1x3+1/3x5+1/5x7+1/7x9+1/9x11=?
计算:1/1x3+1/3x5+1/5x7+...1/2009x2011+1/2011×2013
1/1x3+1/3x5+1/5x7+……+1/99x101
1/1x3+1/3x5+1/5x7+…+1/2011x2013是多少?
1/1x3+1/3x5+1/5x7+.+1/2009x2011=
1/1x3+1/3x5+1/5x7+.+1/1997x1999 简便计算.
1X3分之1+3X5分之1+5X7分之1+...+2013X2015分之1
1分之1x3+1分之3x5+1分之5x7+.+1分之2011x2013
计算1/1X3+1/3x5十1/5X7+.+1/2009x2011