Point P is on the line y=5x+3.The coordinates of point Q are
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Point P is on the line y=5x+3.The coordinates of point Q are(3,-2).If M is the midpoint of PQ,then M must lie on the line
y=5x-7
怎么算的?
y=5x-7
怎么算的?
翻译:
点P在y=5x+3直线上.已知坐标Q(3,- 2).如果M是PQ的中点,则M一定在直线【y=5x-7】上.
不妨设P(a,5a+3)
则M横坐标x=(3+a)∕2,纵坐标y=(5a+3-2)∕2
即a=2x-3 a=(2y-1)∕5
所以2x-3=(2y-1)∕5
化简得:y=5x-7
所以点M一定落在y=5x-7这条直线上
点P在y=5x+3直线上.已知坐标Q(3,- 2).如果M是PQ的中点,则M一定在直线【y=5x-7】上.
不妨设P(a,5a+3)
则M横坐标x=(3+a)∕2,纵坐标y=(5a+3-2)∕2
即a=2x-3 a=(2y-1)∕5
所以2x-3=(2y-1)∕5
化简得:y=5x-7
所以点M一定落在y=5x-7这条直线上
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