一道数学会考题：已知函数f(x)=sin(2x+π/3)+cos(2x-π/6)

已知函数f(x)=cos(2x-π/3)+sin^2 x-cos^2 x 已知函数f(x)=cos(2x-π\3)+sin²x-cos²x 高一数学 已知函数F(X)=SIN(π-X)SIN(π/2-X)+COS*X 已知函数f(x)=cos(2x-π/3)+sin^2x-cos^2x,设函数g(x)=[f(x)]^2+f(x),求g( 已知函数f(x)= [sin(2π-x)sin(π+x)cos(-x-π)] ／[2cos(π-x)sin(3π-x)] 已知函数f(x)=cos(π/6-2x)+cos(2x+π/6)+sin(2x+π/3)-sin(π/3-2x). 已知函数f(x)=cos^2(x-π/6)-sin^2x化简 已知函数f(x)=sin(2x-π/6)+cos^2 x 高一三角函数一道 已知函数f(x)=sin(2x-π/6)-2cos²a 已知函数f(x)=2cos(x-π/6)sin(x+π/6)-√3*(sin(x-π/6))^2+sin(x-π/6)c 已知函数f(x)=cos(2x-π/3）+2sin(x-π/4）sin(x+π/4)=sin(2x-π/6) , 已知函数f(x)=2cos(x+π/3)[sin(x+π/3)-√3cos(x+π/3)]