作业帮关于X,Y飞一元一次方程(y²-4x)x²+(y+2)x-5=0,x＝?,Y＝?
已知x²+y²+5=2x+4y,求【2x²-(x-y)(x-y)】【(x+y-1)(x-y
(2x-y)²-4(x-y)(x+2y)
化简：（2x-y)²-4(x-y)(x+y)
|x+y+2|+(2x+3y+5)²＝0 求x y的值.
已知x²+4x+y²-2y+5=0,则x+y=
已知x²+y²-2x+4y+5=0,求x+y
已知x²+4x+y-2y+5=0求x+2y
(x+y)²+4(x+y)-5
若|x+2y-1|+y²+4y+4=0,求（2x-y）²-2（2x-y)(x+2y)+(x+2y)&
已知x/y=2,求2x(x+y)-y(x+y)/4x²-4xy+y²
已知x²+y²+5=2x+4y,求代数式（2x²-（x+y)(x-y))x((x+y-1)
已知x*x+4x+y*y-2y+5=0,则x*x+y*y=?