cosα+sinα=√6/2(0<α<π/4)则α=
三角函数题2sin^2α-cos^α+sinα*cosα-6sinα+3cosα=0 求(2cos^α+2sinαcos
已知tanα=2,sinα+cosα<0,求[sin(2π-α)*sin(π+α)*cos(-π+α)]/[sin(3π
若sinα/√(1-cos^2 α)+√(1-sin^2 α)/cosα=0,则式子cos(sinα)的符号?sin(c
已知cos(π/2-α)-2cosα=sinπ,且cosα<0,则sinα的值为?
已知0<α<π/2,且3sinα=4cosα求(sin^2α+2sinαcosα)/(3cos^2α-1)求cos^2α
已知3sinα-2cosα=0,求(cosα-sinα)/(cosα+sinα)+(cosα+sinα)/(cosα-s
已知向量a=(sinα+cosα,√2sinα),b=(cosα-sinα,√2cosα),a∈[0,π/2],且
已知α∈(0,π/2),且2sinα-sinαcosα-3cosα=0.求[sin(α+π/4)]/[sin2α+cos
比较大小sin(cosα)与cos(sinα)(0<α<π/2)
若sin^2α+sinα=1 则cos^4α+cos^2α=
已知(sinα-cosα)/(sinα+cosα)=1/3,则cos^4(π/3+α)-cos^4(π/6-α)的值为
sin²α+√3sinαcosα-2cos²α=0,α∈(π/6,5π/12),求:(1)sin(2