因式分解 ① x(b+c-d)-y(d-b-c)-z(c+b-d) ②(a-b)^2-2(a-b)(a+b)+(a+b)
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因式分解 ① x(b+c-d)-y(d-b-c)-z(c+b-d) ②(a-b)^2-2(a-b)(a+b)+(a+b)^2 ③4(5a-b)^2-9(2a+3b)^2
① x(b+c-d)-y(d-b-c)-z(c+b-d)
=xb+xc-xd-yd+yb+yc-zc-zb+zd
=b(x+y-z)+c(x+y-z)-d(x+y-z)
=(x+y-z)(b+c-d)
②(a-b)²-2(a-b)(a+b)+(a+b)²
=[(a-b)-(a+b)]²
=(-2b)²
=4b²
③ 4(5a-b)²-9(2a+3b)²
=[2*(5a-b)]²-[3*(2a+3b)]²
=(10a-2b)²-(6a+9b)²
=[(10a-2b)+(6a+9b)][(10a-2b)-(6a+9b)]
=(16a+7b)(4a-11b)
=xb+xc-xd-yd+yb+yc-zc-zb+zd
=b(x+y-z)+c(x+y-z)-d(x+y-z)
=(x+y-z)(b+c-d)
②(a-b)²-2(a-b)(a+b)+(a+b)²
=[(a-b)-(a+b)]²
=(-2b)²
=4b²
③ 4(5a-b)²-9(2a+3b)²
=[2*(5a-b)]²-[3*(2a+3b)]²
=(10a-2b)²-(6a+9b)²
=[(10a-2b)+(6a+9b)][(10a-2b)-(6a+9b)]
=(16a+7b)(4a-11b)
[a,b)×[c,d
a,b ,c ,d
第一类:A B C D.X Y Z;
a,b,c,d>0 证(a/(b+2c+3d))+(b/(c+2d+3a))+(c/d+2a+3b))+(d/(a+2b
b/a(a+b)+c/(a+b)(a+b+c)+d/(a+b+c)(a+b+c+d)
已知a/b=c/d,求证a+2b/b=c+2d/d
求行列式 |a+b+c+2d a b c,d b+c+d+2a b c,d a a+c+d+2b c,d a b a+b
( )-(c-d)=(a-c)-(-b+d)
A B C D × 9 ___________________ D C B A (1) A = ( )(2) B = (
分解因式(a-b)(c+d)-(a-b)(c-d)
已知a>b,c>d,求证a+c>b+d.
a b c d* d_________=d c b a