求值sin(π/2)*sin(π/3)+2cos(-π/2)-根号3*tan(π/3)
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求值sin(π/2)*sin(π/3)+2cos(-π/2)-根号3*tan(π/3)
sin(π/2)*sin(π/3)+2cos(-π/2)-√3*tan(π/3)
=sin(π/3)+0-√3*tan(π/3)
=√3-√3*√3
=√3-3
再问: 答案是二分之根号三-根号三吧 sin(π/3)=二分之根号三。 是吧??
再答: sin(π/3)=二分之根号三。不好意思 sin(π/2)*sin(π/3)+2cos(-π/2)-√3*tan(π/3) =sin(π/3)+0-√3*tan(π/3) =√3/2-√3*√3 =√3/2-3
=sin(π/3)+0-√3*tan(π/3)
=√3-√3*√3
=√3-3
再问: 答案是二分之根号三-根号三吧 sin(π/3)=二分之根号三。 是吧??
再答: sin(π/3)=二分之根号三。不好意思 sin(π/2)*sin(π/3)+2cos(-π/2)-√3*tan(π/3) =sin(π/3)+0-√3*tan(π/3) =√3/2-√3*√3 =√3/2-3
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