计算9(x^2+1)=10
已知x=根号2-1,计算x^10+2x^9-2x^8-2x^7+x^6+3x^2+5x+1的值
计算:(x+1)x=7 (x-1)(x+2)=30 (3-x)(3-x)+x=9
计算:x^2-x=?
计算:10x/2x-1+5/1-2x
2x-1/3-10x-1/6-2x+1/4=1怎样计算?
2x+1/4-1=x-10x+1/12,救命,计算啊
计算:x-[(10x+1)/6]=[(2x+1)/4]-1
计算:1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(x+3)+……+1/(x+9)(x+10)
计算:(1/X^2+3X+2)+(1/X^2+5X+6)+(1/X^2+7X+12)=(1/X^2+9X+20)
计算:1/(x^2-7x+10)+1/(x^2-x-2)+1/(x^2+5x+4)+1/(x^2+11x+28)=( )
分式计算:①(1/x-4)-(2/x-3)=(3/x-2)-(4/x-1) ②(x+3/x+4)+(x+8/x+9)=(
计算:∫(2x-1)的10次方dx=