√2/2sin2x+√2/2(sin^2x-cos^2x)怎么化简成sin(2x-π/4)
函数f(x)=-√2(sin2x+π/4)+6 sin x cos x-2cos²x+1
求函数fx=(sin^4x+cos^4x+sin^2x*cos^2x)/(2-sin2x)
化简:2cos2x+2sin^2 x+cos(-x)分之sin2x+sin(π-x)=___________
已知cos(x+π/4)=3/5求sin2x-2sin^2x
两个个数学证明题1.证明:cos2x+sin2x=√2sin(sin2x+π/4)2.证明:αsinαx+cosαx=√
1.y=cos^4x+sin^4x 求周期 2.y=(sin2x+sin(2x+π/3))/( cos2x+cos(2x
已知COS(π/4-X)=-4/5,求(SIN2X-2SIN^X)/(1+TANX)
(sin^2x+cos^2x )(sin^2x-cos^2x)怎么得sin^2x-cos^2x?
化简(1)√3sin x+cos x (2)√2(sin x-cos x) (3)√2cos x-√6sin x
已知tan=2,求(cos x+sin x)/(cos x-sin x)+sin^2x
已知α,x∈R,函数f(x)=sin2x-(2√2+√2 a)sin(x+π/4)- 2√2 /cos(x-π/4).(
tan(π/4-x)=-1/3,sin^2 (x+π/4) /(2cos^2 x+sin2x)=?