已知x^2y+y^2x-2=0,则当经过x=1 .y=1时,dy/dx=
dy/dx,y=(1+x+x^2)e^x
dy/dx-y/x=x^2
设xy-xe^(y^2)-x=-2,则当x=1,y=0时,dy/dx=
dy/dx+(2/x)y=-x当y(2)=0时,
dy/dx=x(1+y^2)/y通解
dx/dy=x/y+[cos(x/y)]∧2,y(0)=1
y(x + y + 1) dx + (x + 2y) dy = 0:运用正合方程式求解
dy/dx-2y/(x+1)=(x+1)^2
dy/dx-2y/(1+x)=(x+1)^3
dy/dx=(e^x+x)(1+y^2)通解
已知函数y=x(x-1)(x-2)(x-3)求导数值dy/dx ,
(x^2)dy+(y^2)dx=dx-dy