已知、AB=AD,AC=AE,∠DAB=∠EAC,BE、CD交于点P.求证：PA平分∠DPE.

如图,已知AB=AD,AC=AE,∠DAB=∠EAC,BE,CD交于P,求证:AP平分∠DPE 已知,如图所示,AB=AC,AD=AE,∠DAB=∠CAE,CD与BE相交于P、求证 PA平分∠DPE 已知:如图AB=AC,AD=AE.AB,DC相交于点M,AC,BE相交于点N,∠DAB=∠EAC.求证:∠D=∠E 已知:如图,AB=AC,AD=AE,BE、CD交于点G.求证:AG平分角BAC 15如图,AB=AC,AD=AE.AB、DC相交于M,AC、BE相交于N,∠DAB=∠EAC.求证：AM=AN 如图6,AB=AC,AD=AE,∠DAB=∠EAC,AB、DC相交于点M,AC、BE相交于点N,BE、CD相交于点O,证 如图，AB=AC，AD=AE，AB，DC相交于点M，AC，BE相交于点N，∠DAB=∠EAC．求证：△ADM≌△AEN． 如图所示,在△ABC和△ADE众,AB=AC,AD=AE,∠DAB=∠EAC,AD,AE交BC于点F,G.求证DE‖B 已知：如图AD//BC,AE和BE分别平分∠DAB和∠CBA,CD过点E.求证：AB=AD+BC 如图,已知AC平分∠DAB,CE⊥AB于E,CD=CB,求证=½(AB+AD) 已知AD⊥AB,AC⊥AE,且AD=AB,AC=AE,CD分别交AB,BE于点G,F 求证1）∠B=∠C 2）BE⊥CD 如图,AB=AC,AD=AE,CD=BE,求证,角DAB=角EAC