设实数a、b满足a2-8a+6=0及6b2-8b+1=0,求ab+1ab
已知实数a,b满足 a2+b2=ab+a+b-1,求a+b的值.
若实数a,b满足a2+a-1=0,b2+b-1=0,则ab+ba
若实数a,b满足a2+ab-b2=0,则a/b=?
若实数a,b满足a2+ab-b2=0,则ab
已知实数a.b满足下列关系a2-5a+2=0,2b2-5b+1=o求(ab+1)/b的值
已知两实数ab满足条件a2-3ab+2b2=0,求a比b的值
已知实数a、b满足a2+ab+b2=1,且t=ab-a2-b2,求t的取值范围.
已知实数a,b满足ab=1,那么1/(a2+1)+1/(b2+1)=?
实数a,b 满足a2+b2=1 则ab范围
若实数a,b满足条件(a/b)+(b/a)=2,求(a2+ab+b2)/(a2+4ab+b2)的值
已知|a+1|+(2a-b)2=0,求3ab-15b2+5a2-6ab+15a2-2b2的值.
已知实数a,b满足(a+b)2=1,(a-b)2=25,求a2+b2+ab的值