If dy/dx=2y^2 and if y= -1 when x=1,then when x=2,y=?
dy/dx=x(1+y^2)/y通解
dy/dx-y/x=x^2
dy/dx,y=(1+x+x^2)e^x
(x^2)dy+(y^2)dx=dx-dy
从(dx)/(dy)=1/y '导出:(d^2x)/(dy^2)=-y''/(y')^3
dy/dx-2y/(x+1)=(x+1)^2
dy/dx-2y/(1+x)=(x+1)^3
dy/dx=(e^x+x)(1+y^2)通解
微分方程 dy/dx=(-2x)/y
dy/dx=2y/x+3x/2y
求dy/dx=(x-y+5)/(x+y-2)
试从dx/dy=1/y'导出:d^2x/dy^2=-y''/(y')^3 题目中关于d[1/y']/dx}*[dx/dy