18x + 9y + 3z = 63 12x + 11y + 6z = 50 14x + 6y + 10z = 48 怎

解方程组{x(x+y+z)=6,y(x+y+z)=12,z(x+y+z)=18 如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y, (x+y-z)(x-y+z)= 解方程组1、4x+9y=12,3y-2z=1,2x+6z=32、3x-y+2z=3,2x+y-3z=11,x+y+z=1 1.x+y=16,y+z=12,z+x=102.3x-y+z=4,2x+3y-z=12,x+y+z=63.x+y+z=6 2x+3y+z=11,3x+y-z=2,x+y+z=6求解 {x+y+z=6,2x-y+z=3,3x+9y+z=24 解方程组{3x+y-z=4,2x-y+3z=12,x+y+z=6} 解方程{3x -y+z=4 2x+3y-z=12 x+y+z=6 {2x+3y-4z=-5 x+y+z=6 x-y+3z=10 x+y+z=4 2x+3y-z=6 3x+2y+2z=10 3x+7y+z=5 ,4x+10y+z=6 ,x+y+z=