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求下列式子dy/dx (1) x^2y-x+y=0;(2) x√y =y-1
若|x+2y-1|+y²+4y+4=0,求(2x-y)²-2(2x-y)(x+2y)+(x+2y)&
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微分方程y''=3√y,x=0,y=1,y'=2
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y=ln(x+√x^2+1),求y
y=1-x^2 x>=0 ,y=sin|x|/x x