(1+0.228-0.21)(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)(0.

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/07/14 16:36:50

(1+0.228-0.21)*(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)*(0.228-0.21)巧算?
写清思路

若设0.228-0.21=0.018=x
则(1+0.228-0.21)*(0.228-0.21+0.2003)-(1+0.228-0.21+0.2003)*(0.228-0.21)
=（1+x）（x+0.2003)-(1.2003+x)*x
=x+0.2003+x方+0.2003x-1.2003x-x方
=0.2003

计算(1+0.21+0.32)x(0.21+0.32+0.43)-(1+0.21+0.32+0.43)x(0.21+0. (1+0.21+0.32)*(0.21+0.32+0.43)-(1+0.21+0.32+0.43)*(0.21+0.32 （1+0.21+0.32）*（0.21+0.32+0.43）-（1+0.21+0.32+0.43）*（0.21+0.32 0.21其中21循环+0.21其中1循环+0.21=?用分数表示 110分之1乘2.1乘0.54乘55分之54乘0.21乘0. 简便运算:0.61×0.25+0.81×1/4+0.21×25% 2.5*0.4+0.21*3 0.21除以35 巧算0.39×0.21 用简便方法计算3.25*7.8+3.25*0.21+0. =ROUND(RAND()*(0.611-0.51)+0.21,1)怎么让后面出现两位小数 0.21÷X=2又3分之1 解方程