x=y+2 10x+y=2(x+10y)-17 把它解出来
已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y
解方程组:(x+3)(y-2)=(x-3)(y+10),(x+1)(y+3)=(x-2)(y+12)
解方程组 2x+y(y-2x)=9 (x+y)(x+y-3)=10
解方程组:2/(x+y)+5/(x-y)=18 9/(x+y)-10/(y-x)=66
解方程组:2/(x+y)+5/(x-y)=18 9/(x+y)-10/(y-x)=66
解方程组 10(x-y)=3(x+y)+15 6(x+y)=4(2x-y)+16
解方程组X+Y/2=3X-2Y=10+6X+Y/4
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai
解二元一次方程1.x+y=3 2.x-y=-5 3.x=3y 4.4x-3y=17 5.3x+y=10 x-y=2 3x
[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x其中x=2012 y=2013
解方程组(x+y)(x-2y)=-5 (x-y)(x+2y)=7
[数学]x的平方-y的平方-x+3y-2=0,把它因式分解