cos (x/2) - sinx=0求x
f ' (sinx)=cos^2x,求f(x)
求函数y= cos^2x+ sinx (| x |
sinx+cosx/sinx-cosx=2 求sinx/cos^3x +cosx/sin^3x
已知(2sinx+cosx)(sinx+2cosx-3)=0 求sin 2x+cos 2x/tan 2x
若 f(sinx+1/sinx)=csc^2x-cos^2x,求f(x)
cos(x)^2+sinx 求范围.
已知cos(x-90)=十分之根号2,求sinX
请教 g(sinx)=cos^2x+sinx-1 求g(x),请写详细步骤.
求极限:lim(1/sinx^2x-(cos^2x)/x^2) X趋于0
利用lim sinx/x =1或等价无穷小量求极限 lim (cosαx-cosβx)/x^2 x趋向0
已知sinx=根号3/3,求sinx+cos(派+x)/sinx+sin(派/2-x)的值
求多元函数极值f(x,y)=sinx+cosy+cos(x-y),0≤x,y≤π/2