4(x-2)²-(x-1)²=0
解方程 x(x+1)(x²-2x-4)=0 x³-2x+1=0 x的4次方+8x³+14x
设f (x)={2x+1(x≥0),x²+4(x
解方程(x²-x+4)x-(x-1)(x²+2)=x+7
(x+2)/x(x-2)-(x-1)/x²-4x+4=几,
已知函数f(x)=x²+x+1,x≥0;2x+1,x
已知f(x)={x²-3x+4(x>0),{1-x(x
因为x²-x+2=(x-1/2)²+7/4>0所以x(x²-x+2)
x²+3x-2=0,x²-6x-6=0,3x²-4x-1=0,3x²+10x+3
(x-2)²=(2x-3)² x²-4x=0 3x(x+1)=3x+3 x²-2
3x²-(x-2)=0 (2x-1)(x+3)=4 x²-3x-4=0 x²-3x+18=
2x(x-1)=0 x²+4=4x (x-3)(x+1)=0 x²-3x+1=0
(X-1)(X-2)=70,(3-X)²+2X(X-1)=0,-3X²-4X+4=0,(3-X)