若(x+y)(x+y-1)-12=0,求x+y的值.
若|x+y-1|+(x-y-2)²=0,求代数式(x+2y)(x-2y)-(2x-y)(-y-2x)的值.
(X+y)(x+y-1)-12=0求x+y的值
若x-y=1,求代数式x(x-y)+y(y-x)+2013的值
已知x-y/x=x/x-2y(y不等于0),求x:y的值
若|x+2y-1|+y²+4y+4=0,求(2x-y)²-2(2x-y)(x+2y)+(x+2y)&
已知x,y都是自然数,且有x(x-y)-y(y-x)=12,求x、y的值.
(1)已知x+y=6,x²-y²=5,求x-y的值(2)若x+y=3,x²+y²
若根号(x+y+1)+(x-2y)的平方=0,求x-y的值
若X-2Y+6+(X+Y+12)²=0,求4X+ 5Y的值
(x+y)(x+y+10)+25=0 x-y=3.求x,y的值
若(2x+y-1)²+|x-2y-3|=0,求代数式(3x+y)(3x-y)-(x+2y)(x-y)-3的值
已知x=3分之1,y=二分之一,求代数式x-(x+y)+(x+2y)-(x+3y)+...-(x+13y)的值