化简sin(2π-α)tan(α+π)tan(-α-π)/
证明(tanα×sinα)/(tanα-sinα)=(tanα+sinα)/(tanα×sinα)
若f(α)=[sin(π-α)cos(2π-α)tan(-α+π)]/[-tan(-α-π)sin(-π-α)]化简
化简sin³(﹣α)cos(2π+α)tan(2π-α)/sin(α-2π)cos(α-3π/2)-tan(π
[sin(2π+α)·tan(-α)·cos(-α)]÷[sin(-α)·cos(2π+α)·tan(2π+α)化简
化简:[sin(π+α)*cos(π-α)*tan(π-α)]/[cos(π/2+α)*tan(3π/2-α)*tan(
已知α∈(0,π|2),2tanα+3sinβ=7,且tanα-6sinβ=1,求sinα的值
证明:(1)tanα−tanβtanα+tanβ=sin(α−β)sin(α+β)
化简tanα(cosα-sinα)+sinα+tanαcotα+cscα
α是第三象限角,f(α)={sin(α-π/2)cos(3π/2+α)tan(π-α)}/{tan(-α-π)sin(-
已知f(α)=sin(π-α)cos(2π-α)tan(-α+3π/2)tan(-α-π) /sin(-π-α).(1)
化简sin(2π-α)*tan(π+α)*cot(-α-π)/cos(π-α)*tan(3π-α)(急)
②若cos(已知α是第三象限角f(α)=sin(π-α)cos(2π-α)tan(-α-π)/tan(-α)sin(-π