计算:「(a^2+2ab)^2」/(a+b)^2 (x^3-xy^2)/「-(x+y)」 (2x-5)^2=(-1+x)
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计算:「(a^2+2ab)^2」/(a+b)^2 (x^3-xy^2)/「-(x+y)」 (2x-5)^2=(-1+x)^2 解方程
「(a^2+2ab)^2」/(a+b)^2
=「(a(a+2b))^2」/(a+b)^2
=a^2(a+2b)^2/(a+b)^2
(x^3-xy^2)/「-(x+y)」
= x(x^2-y^2)/「-(x+y)」
= x(x+y)(x-y)/「-(x+y)」
=-x(x-y)
(2x-5)^2=(-1+x)^2
(2x-5)^2-(x-1)^2=0
(2x-5+x-1)(2x-5-x+1)=0
(3x-6)(x-4)=0
x=2 或x=4
=「(a(a+2b))^2」/(a+b)^2
=a^2(a+2b)^2/(a+b)^2
(x^3-xy^2)/「-(x+y)」
= x(x^2-y^2)/「-(x+y)」
= x(x+y)(x-y)/「-(x+y)」
=-x(x-y)
(2x-5)^2=(-1+x)^2
(2x-5)^2-(x-1)^2=0
(2x-5+x-1)(2x-5-x+1)=0
(3x-6)(x-4)=0
x=2 或x=4
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