log8(9)*log27(32)=?
log8^9.log27^32+lg25+lg2.lg50+lg2.lg2
关于log的计算log8(9)* log27 (32)log4 (3) *log9(2)- log 1/2(四倍根号下3
lg2分之1减lg5分之8加lg12.5减log8的9次方×log27的8次方
(log8 9/log2 3)=?
(9/4)^(-1/2)+log8 9*log3 32=
计算log8底9*log3底32
用q=log27(32) p=log9(25).表示lg5
计算:log27(32)×log64(27)+log9(2)×log4(√27)=
(log4(3)+log8(3))*(log3(2)+log8(2))-log1/2(^4√32)=?
已知log2^3=a.则log8^3= log8^9=
log3(2)*log8(9)
log8(9)*log2(3)