(x-36)/(10-8)=(x+36)/(12-8)
(x+12)(x-2)+(x+7)(x+8)-(x+5)(x-10),其中x=2
x-36=(x/8+8)+(x/5+10)
(x+10)+(X+8)+X\3=36
(x+x+10+x+8)×3=36怎么解?
1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550
若根号下x^+8x+16+根号下x^-12x+36=10,化简|2x+8|+|2x-12|
解方程x²+x-6分之5x+x²-x-12分之2x-5=x²-6x+8分之7x-10
解分式方程(5-2x)/(x^2-x-12)=5x/(x^2+x-6)+(10-7x)/(x^2-6x+8)得
解方程.(5x/x²+x-6)+(2x-5/x²-x-12)=7x-10/x²-6x+8
解方程(x/x(x+2))+(x/(x+2)(x+4))+.+x/(x+8)(x+10)=1
(2x^-5x+2/6x^+13x+6)*(6x^-5x-6/6x^-17x+10)*(12x^+8x-15/2x^-x
解方程 (x-8)+x=36