化简：(sin^6a+cos^6a-1) / (sin^4ª+cos^4a-1)

1-sin^6a-cos^6a分之1-sin^4a-cos^4a 化简 化简1-sin^4a-cos^4a/1-sin^6a-cos^6a 化简(1-sin^6 a-cos^6 a)/(cos^2 a-cos^4 a)== 求值:1-sin^6a-cos^6a/1-sin^4a-cos^4a (1-sin^4a-cos^4a)/(1-sin^6a-cos^6a) （1-sin^6a-cos^6a)/(1-sin^4a-cos^4a)=? (1-sin^6a-cos^6a)/(sin^2a-sin^4a) 化简 1-sin^4a-cos^4a/cos^2a-cos^4a (1-sin^6 a-cos^6 a)/(1-sin^4 a-cos^4 a)的化简结果 若sin^4a/sin^2b+cos^4a/cos^2b=1,证明sin^4b/sin^2a+cos^4b/cos^2a 证明sin(4A)sin(2A)(1-cos(2A)) cos(4A)cos(2A)(1 cos(2A))=cos(2A 化简Sin A + Sin 2A / 1+cos A +