log3(x2)+log9(1/x)+3/2=0怎么解
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log3(x2)+log9(1/x)+3/2=0怎么解
log3(x2)+log9(1/x)+3/2=0
2log3(x)+log3^2(x^-1)+3/2=0
2log3(x)-1/2log3(x)=-3/2
3/2log3(x)=-3/2
log3(x)=-1
x=1/3
再问: 1/2log3(x)是哪一个运算律得出的?
再答: log9(1/x), 底数9=3^2,真数1/x=x^-1, log(a^n)b^m=m/nlog(a)b
再问: 比如loga^2(m)=1/2loga(m)????
再答: 是的
2log3(x)+log3^2(x^-1)+3/2=0
2log3(x)-1/2log3(x)=-3/2
3/2log3(x)=-3/2
log3(x)=-1
x=1/3
再问: 1/2log3(x)是哪一个运算律得出的?
再答: log9(1/x), 底数9=3^2,真数1/x=x^-1, log(a^n)b^m=m/nlog(a)b
再问: 比如loga^2(m)=1/2loga(m)????
再答: 是的
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