tan(a b)=4,cot(a-b)=-3,求tan2a和tan2b
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/07/19 16:06:18
tan(a b)=4,cot(a-b)=-3,求tan2a和tan2b
tan(a+ b)=4,cot(a-b)=-3,→tan(a- b)=-1/3
(1).tan2a=tan[(a+ b)+(a-b)]=
[tan(a+b)+tan(a- b)]/[1-tan(a +b)tan(a- b)]=
[4-1/3]/[1-4*(-1/3)=(11/3)/(7/3)=11/7
(2).tan2b=tan[(a+ b)-(a-b)]=
[tan(a+b)-tan(a- b)]/[1+tan(a +b)tan(a- b)]=
[4-(-1/3)]/[1+4*(-1/3)=(13/3)/(-1/3)=-13
(1).tan2a=tan[(a+ b)+(a-b)]=
[tan(a+b)+tan(a- b)]/[1-tan(a +b)tan(a- b)]=
[4-1/3]/[1-4*(-1/3)=(11/3)/(7/3)=11/7
(2).tan2b=tan[(a+ b)-(a-b)]=
[tan(a+b)-tan(a- b)]/[1+tan(a +b)tan(a- b)]=
[4-(-1/3)]/[1+4*(-1/3)=(13/3)/(-1/3)=-13
tan(a+b)=3,tan(a-b)=5,求tan2a和tan2b的值
tan(a+b)=3 tan(a-b)=5 求tan2a tan2b的值
已知tan(a+b)=3,tan(a-b)=5,求tan2a,tan2b的值~
tan(a+b)=5,tan(a-b)=3求tan2a,tan2b的值?
tan(A+B)=3,tan(A-B)=5,求tan2A,tan2B.(A,B是角)
已知tan(a+b)=3,tan(a-b)=5,求tan2a,tan2b的值.辛苦
已知tan(a-b)=1/3,tan(a+b)=1/2,求tan2a,tan2b的值
tan(a+b)=2/5,tan(a-b)=1/4,求tana,tanb,tan2a
已知tan(a+b)=3,tan(a-b)=5 试求:tan2a和tan2 b的值
已知tan A= 4,cot B=1/3,则tan ( A+B)=?
证明tan(π/4+a)-cot(π/4+a)=2tan2a
若cos(a+b)=-1,tan a=2,求cot b的值