2m-5=n 1+2n=3m求解啊
(3m-2n)(3m+2n+1)求解
已知m/n=5、,求(m/(m+n))+(m/(m-n))-(n^2/(m^3-n^2))
(5m+3n)^2-(m-3n)(25m-3n),其中m=1,n=2
已知m-2n=3.求[(3m+2n)(3m-2n)-(m+2n)(5m-2n)]÷1/3 m 的值.
设m n为自然数,定义m*n=m+(m+1)+(m+2)+(m+3)+.(m+n)
m-{n-2m+[3m-(6m+3n)+5n]}=
集合M={X=3m+1,m∈N*},N={y/y=5n+2,n∈N*},则M∩N=?
已知3m=2n,则m/(m+n)+n/(m-n)-n^2/(m^2-n^2)=?
若2m-n/m+2n=5,求3(2m-n)/m+2n-m+2n/2m-n+3的值
诺2m-n/m+2n=5,求3(2m-n)/m+2n-m+2n/2m-n+3的值
已知m-2n/2m+n=5,求代数式3(m-2n)/2m+n-15(2m+n)/m-2n-2
如果m和n互为相反数,则m+2m+3m+4m+5m+5n+4n+3n+2n+n=