3.7 整式的除法答案.求秒啊.
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/08/28 08:32:41
3.7 整式的除法答案.求秒啊.
![](http://img.wesiedu.com/upload/e/ff/eff22044556e250d8808d87907778063.jpg)
![](http://img.wesiedu.com/upload/1/e3/1e30dcd145cfd570d20b79e20c0fd28a.jpg)
![](http://img.wesiedu.com/upload/3/ce/3ce8cf87a457696ca0392a1f79eb6b92.jpg)
![](http://img.wesiedu.com/upload/e/ff/eff22044556e250d8808d87907778063.jpg)
![](http://img.wesiedu.com/upload/1/e3/1e30dcd145cfd570d20b79e20c0fd28a.jpg)
![](http://img.wesiedu.com/upload/3/ce/3ce8cf87a457696ca0392a1f79eb6b92.jpg)
2.(1)2a^2 (2)-15a^2b^2 (3)2m^2-3n^2 (4)3y-4y^2 3.(1)
(-3/4 b^2 c)∕(3b)
=(-1/4) b^(2-1) c
=(-1/4) bc
(2)(8*10^7)∕(-2*10^3)
=-4*10^(7-3)
=-4*10^4
(3)(3 m^2 n^3)∕(mn)^2
=3 m^(2-2) n^(3-2)
=3n (4)(15 x^3-10 x^2)∕5x
=3 x^(3-1) - 10x^(2-1)
=3x^2-2x
8.47×10^10÷(1.75×10^3×100000)
=(8.47×10^10)÷(1.75×10^8)
=4.84×10^2
=484
答:三峡工程一年所发的电能供该市居民使用484年.
5.x·(9x^3y-3xy^2)÷(-3x^2y)
=(9x^4y-3x^2y^2)÷(-3x^2y)
=-3x²+y
[(x+y)^2-(x-y)^2]÷(-4xy)
=(x²+2xy+y²-x²+2xy-y²)÷(-4xy)
=4xy÷(-4xy)
=-1
6.木有.(有可能会有错误,你自己检查吧,我是学习渣.奸笑ing.)
(-3/4 b^2 c)∕(3b)
=(-1/4) b^(2-1) c
=(-1/4) bc
(2)(8*10^7)∕(-2*10^3)
=-4*10^(7-3)
=-4*10^4
(3)(3 m^2 n^3)∕(mn)^2
=3 m^(2-2) n^(3-2)
=3n (4)(15 x^3-10 x^2)∕5x
=3 x^(3-1) - 10x^(2-1)
=3x^2-2x
8.47×10^10÷(1.75×10^3×100000)
=(8.47×10^10)÷(1.75×10^8)
=4.84×10^2
=484
答:三峡工程一年所发的电能供该市居民使用484年.
5.x·(9x^3y-3xy^2)÷(-3x^2y)
=(9x^4y-3x^2y^2)÷(-3x^2y)
=-3x²+y
[(x+y)^2-(x-y)^2]÷(-4xy)
=(x²+2xy+y²-x²+2xy-y²)÷(-4xy)
=4xy÷(-4xy)
=-1
6.木有.(有可能会有错误,你自己检查吧,我是学习渣.奸笑ing.)