(10x+x+2)^2-[x+10(x+2)]=138怎样解
解方程(x/x(x+2))+(x/(x+2)(x+4))+.+x/(x+8)(x+10)=1
(x+12)(x-2)+(x+7)(x+8)-(x+5)(x-10),其中x=2
(10-2x)(20+x)=28怎样解?
1/x(x+1)+1/(x+1)(x+2)+...+1/(x+9)(x+10)=1/(x+10),解方程
解方程:(2x+5)(4x*x-10x+25)=8x(x*x+1)
x+2x×10=10x+2x+36
方程x (2x-10) 2(x-12)=236怎样解
|X-1|+|X-2|+|X-3|+|X-4|+|X-5|+|X-6|+|X-7|+|X-8|+|X-9|+|X-10|
y=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10)的导数在x=1
设函数f(x)=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10),
解分式方程(5-2x)/(x^2-x-12)=5x/(x^2+x-6)+(10-7x)/(x^2-6x+8)得
x/(x-2)+(x+9)/(x-7)=(x+1)/(x-1)+(x-8)/(x-6)怎样解这道方程