若实数x、y满足x2+6x+x−y+1+9=0
已知实数x,y满足关系式x2+y2-6x-4y+12=0
若实数x,y满足x-y+1>=0,x+y>=0,x
若实数x,y满足x-y+1》=0,x+y>=0,x
若实数x,y满足(x+x
若实数x,y满足X2+y2-2X+4y=0,则x-2y的最大值为?
已知实数x,Y满足x2+y2+4x-6y+13=0,则x(-Y)=
已知实数x,y满足x2+3y2+6x-12y+21=0,求x,y的值
已知:实数x、y满足x2+y2-4x-6y+13=0则y的x次方=
已知实数x,y满足(x2)+(y2)-xy+2x-y+1=0,求x,y的值
已知实数x、y满足X2+y2-xy+2x-y+1=0,试求x、y的值
若实数x,y满足x−y+1≥0x+y≥0x≤0
若实数x,y满足x≥1x+y≤4x−2y+c≤0