设x=lncos t ,y=sin t - t*cos t
如何x(t)=cos(t)+asin(t) y(t)=sin(t)+bcos(t) expressing x(t) in
设x=e'sin t,y=e'cos t,求dy/dx.
设函数y=y(x)由参数方程x=cos t,y=sin t - t cos t确定,求dy/dx
t=0:pi/100:10*pi; x=2*(cos(t)+t*sin(t)); y=2*(sin(t)-t*cos(t
matlab中t=linspace(0,2*pi,100);x=[t;t]';y=[sin(t);cos(t)]';pl
设x=a cos的3次方t y=a sin的3次方t求dy/dx
matlaB函数问题t = -pi:0.01:pi;x=cos(t)-sin(3*t);y=sin(t)+cos(t);
用matlab 如何作出y与t的图?y=(sin(t)-sin(t0))^2 且 cos t+t*sin t-cos t
1.利用plot函数在区间[0,2π]同时绘制x=sin(t)和y=cos(t),z=sin(t)+cos(t)的图形.
利用plot函数在区间[0,2π]同时绘制x=sin(t)和y=cos(t),z=sin(t)+cos(t)的图形.要求
matlab参数方程绘图x=sin(t);y=cos(t);0
求导:x=cos^4*t,y=sin^4*t,求dy/dx