数学2次根式计算1/6√1又3/5×(-5√3又√3/5)(2)√8/a×√2a/b(3)√2x乘以√2y乘以√x(4)
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数学2次根式计算
1/6√1又3/5×(-5√3又√3/5)(2)√8/a×√2a/b(3)√2x乘以√2y乘以√x(4)2√a÷4√b(5)5√xy÷√5x^3(6)√x-y÷√x+y(7)√x(x+y)÷√xy^2/x+y(x>0,y>0)(8)√xy乘以√6x÷√3y(9)(√mn-√m/n)÷√m/n(n>0)
1/6√1又3/5×(-5√3又√3/5)(2)√8/a×√2a/b(3)√2x乘以√2y乘以√x(4)2√a÷4√b(5)5√xy÷√5x^3(6)√x-y÷√x+y(7)√x(x+y)÷√xy^2/x+y(x>0,y>0)(8)√xy乘以√6x÷√3y(9)(√mn-√m/n)÷√m/n(n>0)
1/6√1又3/5×(-5√3又√3/5)
=1/6√(8/5)×(-5/3√(3/5)
=-5/18√(24/25)
=-5/18×2/5√6
=-1/9√6
(2)√8/a×√2a/b
=√(8/a×2a/b)
=√(16/b)
=4/b(√b)
(3)√2x乘以√2y乘以√x
=√(2x*2y*x)
=2x√y
(4)2√a÷4√b
=√a/2√b
=1/2b√ab
(5)5√xy÷√5x^3
=5√(xy/5x³)
=1/x√5y
(6)√x-y÷√x+y
=1/(x+y)√(x²-y²)
(7)√x(x+y)÷√xy^2/x+y(x>0,y>0)
=√[x(x+y)÷xy²/(x+y)]
=(x+y)/y
(8)√xy乘以√6x÷√3y
=√6x²y÷√3y
=x√2
(9)(√mn-√m/n)÷√m/n(n>0)
=√mn÷m/n-√m/n÷m/n
=n-1
=1/6√(8/5)×(-5/3√(3/5)
=-5/18√(24/25)
=-5/18×2/5√6
=-1/9√6
(2)√8/a×√2a/b
=√(8/a×2a/b)
=√(16/b)
=4/b(√b)
(3)√2x乘以√2y乘以√x
=√(2x*2y*x)
=2x√y
(4)2√a÷4√b
=√a/2√b
=1/2b√ab
(5)5√xy÷√5x^3
=5√(xy/5x³)
=1/x√5y
(6)√x-y÷√x+y
=1/(x+y)√(x²-y²)
(7)√x(x+y)÷√xy^2/x+y(x>0,y>0)
=√[x(x+y)÷xy²/(x+y)]
=(x+y)/y
(8)√xy乘以√6x÷√3y
=√6x²y÷√3y
=x√2
(9)(√mn-√m/n)÷√m/n(n>0)
=√mn÷m/n-√m/n÷m/n
=n-1
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