(X+10)7/12=X+2怎解
(x+12)(x-2)+(x+7)(x+8)-(x+5)(x-10),其中x=2
解方程.(5x/x²+x-6)+(2x-5/x²-x-12)=7x-10/x²-6x+8
(x+2)(x-12)+(x+7)(x+8)+(x+5)(x-10),化简.
1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550
(5x+7)(2x-3)-9x(x-2),其中x=−12
|X-1|+|X-2|+|X-3|+|X-4|+|X-5|+|X-6|+|X-7|+|X-8|+|X-9|+|X-10|
解分式方程(5-2x)/(x^2-x-12)=5x/(x^2+x-6)+(10-7x)/(x^2-6x+8)得
解方程x²+x-6分之5x+x²-x-12分之2x-5=x²-6x+8分之7x-10
x*x+2x+x*x+10x+x*x+25+2x+x*x+1+1+16+x*x+4x*x+9-12x+16x*x+4-1
7:x=14:(2+x)求x
12分之x+10=7X分之x+2
12/7x(x+10)=x+2