(m-n)²=8 (m+n)²=2 则m²-n²=?
已知(m-n)²=8,(m+n)²=,则m²+n²=
mn(m-n)²-n(n-m)³=n(m-n)²( )
先化简再求值[(m+n)(m-n)-(m-n)²]÷(2n),其中m=-2,n=-1/2
若|m-n|+(m+2n-3)²=0,则m+n的值是
(m+n)²-6(m+n)+9=(m+n)²+2(m+n)×(-3)+(-3)²=[(m+
先化简,再求值.8m(m+n)²-2m(m-n)² m=1 n=2
1+n-m/m+2n÷m²-n²/m²+4mn+4n²=
[(m+n)(m-n)-(m-n)²+2n(m-n)]÷4n
已知-m²+2m=4n,-n²+2n=4m,求m/n的值
已知(m-n)²=8,(m+n)²=2,则m²-n²=
1 已知1/n - 1/m - 1/(n+m)=0 则(m/n + n/m)²=
如果m,n为有理数,且满足/m+n+2/+(m-2n+8)²=0,则mn=