yua圆

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/11/06 00:32:10

解题思路：求出圆心和半径，比较半径和2√2；要求圆上至少有三个不同的点到直线l：ax+by=0的距离为2√2 ，则圆心到直线的距离应小于等于 √2 ，用圆心到直线的距离公式，可求得结果．
解题过程：
见附件

最终答案：略

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