由1,3,5,…,2n-1,…构成数列{an},数列{bn}满足b1=2,当n≥2时,bn=abn−1,则b5等于(
数列{an}的前n项和Sn=n2+1,数列{bn}满足:b1=1,当n≥2时,bn=abn-1,设数列{bn}的前n项和
数列[an]的前n项和Sn等于2*n-1,数列[bn]满足:b1=3,bn+1=an+bn,n属于N*.1.证明数列[a
数列[an]的前n项和Sn等于2an-1,数列[bn]满足:b1=3,bn+1=an+bn,n属于N*.1.证明数列[a
已知数列bn,满足b1=1,b2=5,bn+1=5bn-6bn-1(n≥2),若数列an满足a1=1,an=bn(1/b
数列{an}的前n项和Sn=2an-1(n≥1),数列{bn}满足b1=3,b(n+1)=an+bn,求数列{bn}的前
已知数列an bn其中a1=1/2数列an的前n项和Sn=n^2an(n≥1) 数列bn满足b1=2 bn+1=2bn
数列an前n项和为sn,a1=1,数列bn首项b1=2,且sn+n^2=n(an+1),bn=abn-1求an,bn的通
已知等差数列{an}满足a2=3,a5=9,若数列{bn}满足b1=3, bn+1=abn,则{bn}的通项公
已知数列an,bn中,a1=b1=1,且当n≥2时,an-nan-1=0,bn=2bn-1-
已知数列{an}满足an+Sn=n,数列{bn}满足b1=a1,且bn=an-a(n-1),(n≥2),试求数列{bn}
数列an的前n项和为Sn,Sn=4an-3,①证明an是等比数列②数列bn满足b1=2,bn+1=an+bn.求数列bn
已知数列{an},如果数列{bn}满足b1=a1,bn=an+a(n-1)则称数列{bn}是数列{an}的生成数列