(sin10°+cos50°)/(cos10°-sin50°)?

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/07/08 11:57:19

sin10°+cos50°
=sin10°+sin40°
=2sin25cos15
cos10°-sin50
=sin80-sin50
=2cos65sin15
=2sin25sin15
(sin10°+cos50°)/(cos10°-sin50°)
=2sin25cos15/2sin25sin15
=ctg15
=1/tan15
=1/tg(45-30)
=(1+tan45tan30)/(tan45-tan30)
=2+√3

计算1sin50°+3cos50° 求值:2sin50°+cos10°*（1+根号3tan10°）/cs35°cos40°+cos50°cos55° 化简求值2sin50°+cos10°(1+3tan10°)cos35°cos40°+cos50°cos55° sin40°cos10°-SIN10°SIN50°的值是 2sin50°cos50°怎么等于cos50°cos40°+sin50°sin40° 计算sin50°cos40°+cos50°sin40° sin50°*cos40°+cos50°*sin40° sin50°=a cos40°=?cos50°? cos20°cos10°+sin10°sin10° 化简sin10°-根号3*cos10° sin10°sin50°-sin50°sin70°-sin70°sin10°=? 计算 sin10°^2 + sin50°^2 + sin10°sin50° 的值? 答案：3/4