试确定a b的值lim(x^2+1/x+1-ax-b)=1/2
确定a,b的值,使极限等式lim(n→∞)(√(x^2-x+1)-ax-b)=0成立
已知lim{(x^2+1)/(x^3+x)-ax-b}=0(x趋近无穷),求a,b的值
设f(x)=lim(n→∞)(x^(2)e^(n(x-1))+ax+b)/(e^(n(x-1))+1)确定a b 使f(
确定常数a.b 使函数f(x)= ax+b(x>1) x^2(x
lim(x趋向正无穷)(根号(1+x^2)-ax-b)=1,求a,b的值
lim趋向正无穷(根号下X^2+X-1 -AX)=b ,求a ,b
已知lim x→0(((根号下1+x+x^2) - (1+ax))/x^2)=b,求常数a、b的值
试确定常数a,b是极限lim(x趋于0)[1+acos 2x+bcos 4x]/(x^4)存在,并求出它的值
试确定常数a,b,使lim{(3次根号下√(1-x^3 ))-ax-b)=0(x趋于0″ )
1.若lim x趋向无穷 ((4x^2+1)/(x+1)-ax+b)=0,求a,b的值
设lim((x^2+1)/(x+1) -ax-b)=0,求a,b. x趋向无穷大
设lim((x^2+1)/(x+1) -ax-b)=0,求a,b.x趋向无穷大