sin(x-pi)cos(x-pi)=0.25,sin2x
a*sin(pi/4 - x) - b*cos(pi/4 - x) = a*sin(pi/4 + x) - b*cos(
已知函数f(x)=cos(2x-pi/3)+2sin(x-pi)*sin(x+pi/4)
sin(PI()X)+cos(pi()x)的周期
若sin((pi/6)+x)=1/3,则cos((pi/3-x)=?cos((2pi/3)+x)=?
x=0:pi/100:6*pi;b=(cos(x)+i*sin(x))*(x);
Matlab u(x,t)=sin(5*pi*x)cos(5*pi*t)+2sin(7*pi*x)cos(7*pi*t)
sin(x)/(1+cos(x))= -1 -pi小于等于x小于等于pi
函数f(x)=sin^2(x+pi/12)+cos^2(x-pi/12)的最大值
函数y=sin(pi/2+x)cos(pi/6+x)的最大值
y=sin(2x+Pi/3)+cos(Pi/6-2x)周期为
sin(2x+pi/3)=cos(2x-pi/6) 成立吗
y=cos(-pi/2x+pi/2)等于什么