英语翻译The excitation spectrum of CaMoO4:Eu3+ consists of abroa

英语翻译
The excitation spectrum of CaMoO4:Eu3+ consists of a
broad band and some sharp lines.As shown in Fig.3,the
broad excitation band extending to 350 nm is attributable to
the host crystal.The energy absorbed by the host is trans-
ferred to the Eu3+ and produces the red emission.The mech-
anism of energy absorption by the host lattice is not thesame in the long and short wavelength UV regions; these
absorptions are related to charge-transfer processes involv-
ing Mo O and Ca O bands,respectively; while the nar-
row peaks beyond 350 nm result from the f–f transition ab-
sorption of Eu3+ ions.So this novel phosphor can be well
excited by ultraviolet (394 nm) and visible light (464 nm),
nicely in agreement with the widely applied UV LED or blue
LED chips.
It is well known that Eu3+ absorbs no or less energy for
certain excitation wavelengths,and therefore the efficient
Eu3+-activated phosphors mainly depend on the absorption of
host and energy transfer efficiency [6].Remarkably,MoO42−
plays an important role in this novel phosphor.It absorbs the
energy then transfers to Eu3+,which increases the excited
energy of Eu3+ and enhances the emission efficiency.That is
to say,the novel phosphor is a kind of efficient luminescent
material.
3.3.Effect of activator Eu3+ ion concentration
In order to investigate further the significant effect of the
activator ions on the luminescence properties of the novel red
phosphor,the relationship between emission intensity and
concentration of activator ion Eu3+ is listed in Table 1.Gen-
erally,energy migration processes increase the probability
that the optical excitation is trapping at defects or impurity
sites,enhancing non-radiative relaxation.This causes con-
centration quenching,because an increase in the activator
concentration encourages such non-radiative processes.On
the other hand,a decrease in the activator concentration de-
creases the energy stored by the ions.Consequently,there
is an optimum in the activator concentration,resulting from
the trade-off of the above two factors.Seeing from Table 1,
the favorable mole concentration of Eu3+ in CaMoO4:Eu3+
phosphor is 24%.
Additionally,seeing from Table 1,the 536 nm emission
from 5D1 is quenched with the increase in the Eu3+ concen-
tration due to a cross-relaxation process (5DJ → 7D0) →
(7F0 → 7FJ ) [7].At the same time,when the concentration
of Eu3+ is up to 0.30,the highest peak moves to 610 nm,and
the relative intensity decreases sharply.On the other hand,
when the concentration of Eu2O3 is beyond 0.28,the phos-
phor body color is slightly yellow.

激发光谱的CaMoO4：Eu3 +的由一个
宽带和一些尖锐的线条.如图所示.3,
广泛的激发带延伸到350纳米,是由于
主机晶体.东道国吸收的能量转
传送到Eu3 +和产生的红光发射.在机械,
能量由主体晶格吸收anism是不是在长,短的波长紫外线地区thesame,这些
吸收相关的电荷转移过程involv -
荷兰国际集团钼O和钙Ø带,分别;而全国房地产经纪人协会,
超过350纳米结果行峰从F - f过渡AB级
Eu3 +离子的吸附.因此,这种新型荧光粉可以很好地
兴奋的紫外线（394纳米）和可见光（464纳米）,
很好地与广泛应用紫外线LED或蓝色协议
LED芯片.
这是众所周知,Eu3 +的吸收没有或较少的能量为
某些激发波长,因此有效
铕激活的荧光粉主要取决于吸收
主机和能量转移效率[6].值得注意的是,MoO42 -
在这部小说中起着重要的作用荧光粉.它吸收
能量然后转移到Eu3 +的,这增加了激动
能源中Eu3 +和提高发光效率.这是
可以说,小说是一种高效荧光粉发光类
材料.
3.3.植物激活Eu3 +离子浓度
为了进一步调查的显着效果
关于小说的激活离子的发光特性红色
荧光粉,发光强度之间的关系
铕离子的激活剂+浓度见表1.根
口服,能量迁移过程的概率增加
光激发的是套色缺陷或杂质
网站,加强非辐射弛豫.这导致了CON -
中心定位淬火,因为在激活增加
浓度鼓励此种非辐射过程.论
另一方面,在激活剂浓度的降低取消
折痕的离子储存的能量.因此,有
是一个最佳的激活浓度,造成
与贸易有关上述两个因素了.从表一看,
摩尔浓度的有利的CaMoO4中Eu3 +：Eu3 +的
磷为24％.
此外,从表1看到,536 nm发射
从5D1是在淬火与Eu3 +的浓度增加,
tration由于交叉弛豫过程（5DJ→7D0）→
（7F0→7FJ）[7].与此同时,当浓度
中Eu3 +高达0.30,最高峰移动到610纳米,
相对强度急剧下降.另一方面,
当浓度超过0.28铕是,磷酸
普体色略带黄色.
请参考