2x+y-z=10 ,x+3y+2x=14 ,3x-y-2z=7

试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) x/2=y/3=z/5 x+3y-z/x-3y+z x+2y+3z=14 2x+y+z=7 3x+y+2z=11 3x+2y+z=14 ,x+y+z=10,z+2x+3y=1 5 [3x+2y+z=14,x+y+z=10,2x+3y-z=1] (4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai x+2y+3z=14 2x+y+z=7 3x+y+2z=11 求x y z 已知,方程组:4x-3y-7z=0 x+2y=10z 则(x-y+z)÷(x+y+z)=—— 已知x,y,z 大于0,x+y+z=2,求证 xz/y(y+z)+zy/x(x+y)+yx/z(z+x)大于等于2/3 2X+Y+Z=10,X+2Y+Z=-6,X+Y+2Z=8 5X+4Y-3Y=13,2X-3Y+7Z=19,3X-Y=2X 如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y, 若4x-3y-6z=0,x+2y-7z=0,求代数式5x*5x+2y*2y-z*z/2x*2x-3y*3y-10z*10