∫[-∞→∞]e^(-(x-y)^2)dy=∫[-∞→∞]e^(-(y-x)^2)dy=π^1/2 吗?

∫(-∞,+∞)e^[-(x^2+y^2)/2]dy= dy/dx,y=(1+x+x^2)e^x 设y=[e^x+e^(-x)]^2,求dy dy/dx=(e^x+x)(1+y^2)通解 ∫e^(-2x)dx∫e^(-y)dy 求dy/dx y=e^(2x+1) dy/dx+(e^((y^2)+x))/y=0 x=sin(y/x)+e^2 求dy/dx dy/ dx +2y=x*e^x的通解, 微分方程 dy/dx=(e^y+3x)/x^2 y=e^x/x^2+sin2x 求dy/dx ∫（ e^x sin y- y )dx + (e^x cos y - 1)dy,是（2,0）的半圆周y=√2x-x^2