1+(2m+1)/4=9m^2/16怎么解出m?
化简求值(m+2/m²-2m)-(m-1/m²-4m+4)÷(m-1/m) 其中m=4
(1m+3m+5m+...+2009m)-(2m+4m+6m+...=2008m)
当m=1/2时,求15m²-9-{-4m²+[5m-8m²-(2m²-m)+9m
已知m>4,化简|m-4|+|7-2m|+|m×m-2m+1|-|m×m-2m-3|
m²-4m+4/m²-1÷m-2/m+1+2/m-1,其中m=2
解:“(m-2/m+2+4m/m²-4)÷1/4-m²
若(m)(m)-2m=1,则2m-4m+2008的值是-----------
(m+1)(m-1)(m-2)(m-4)
已知:4M^2+9N^2=28M-72N-193,先把下式化简,再求值:(M^2+2M+1)/(M+1)-(M^3-M^
若根号(3m+1)(2-m)=根号3m+1*根号2-m成立 化简 (绝对值m-4) +(根号9m平方+6m+1) +绝对
2m^2-5m+1/m^2 怎么等于(m^2-5M)+m^2+1/m^2
(m+3m+5m+...+2009m)-(2m+4m+...+2008m)怎么算