若a^2+b^2-10a-6b+34=0,问(a-b/a+b)^2÷a^2-b^2/ab×a^2+2ab+b^2/a^2
若a/b=2 则a*a-ab+b*b/a*a+b*b等于?
a+b/2ab
2AB/A+B
(a-b)(a^2+ab+b) 化简
a(a-1)-(a×a-b)=-5,求(a×a+b×b)÷2-ab
若a/b=2,求分式a*a+ab-b*b/a*a-2ab+2b*b
已知a+2b=0,求a*a+2ab-b*b/2a*a+ab+b*b
化简 (a²+b²/a²-b²-a-b/a+b)÷2ab/(a-b)(a+b)&
已知3a*a+ab-2b*b=0(a不等于0,b不等于0),求a/b-b/a-(a*a+b*b)/ab的值.
先化简,再求值;[(2a-b/a b)-(b/a-b)]÷{(a-2b/a b) [ab/(a-b)2]},其中b/a=
因式分解a^+b^+2a^b+2ab^+a^+b^+3ab+a+b
(a^2+b^2/a^2-b^2-a-b/a+b)/2ab/(a-b)(a+b)