计算 2sin10+cos10+tan20sin10,
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/10/06 08:16:58
计算 2sin10+cos10+tan20sin10,
2sin20°+cos10°+tan20sin10°
=2sin20°+cos10°+sin20sin10°/cos20°
=2sin20°+(cos20°cos10°+sin20sin10°)/cos20°
=2sin20°+cos(20°-10°)/cos20°
=2sin20°+cos10°/cos20°
=(2sin20°cos20°+cos10°)/cos20°
=(sin40°+cos10°)/cos20°
=(sin40°+sin80°)/cos20°
=2sin[(40°+80°)/2]*cos[(40°-80°)/2]/cos20°
=2sin60°*cos20°/cos20°
=2*√3/2
=√3
=2sin20°+cos10°+sin20sin10°/cos20°
=2sin20°+(cos20°cos10°+sin20sin10°)/cos20°
=2sin20°+cos(20°-10°)/cos20°
=2sin20°+cos10°/cos20°
=(2sin20°cos20°+cos10°)/cos20°
=(sin40°+cos10°)/cos20°
=(sin40°+sin80°)/cos20°
=2sin[(40°+80°)/2]*cos[(40°-80°)/2]/cos20°
=2sin60°*cos20°/cos20°
=2*√3/2
=√3
cos20/(cos10+sin10)+sin10
根号1-2sin10度cos10度 除以sin10度-根号1-sin10度的平方
(sin20*sin10)/(cos20*cos10)
sin10=?cos10=?
1不查表,求2sin20+cos10+tan20sin10的值 2已知向量a=(2,1+sinx),b+(1,cosx)
化简:根号(1+2sin10°cos10°)
(2cos70°+根号3sin10°)/cos10°
根号 1+2sin10°cos10° 怎样化简
1/2*cos10*sin10*cos20*cos40/cos10到1/4*sin20*cos20*cos40/cos1
化简1−2sin10°cos10°sin10°−1−sin
根号下(1-2sin10°cos10°)除以cos10°-根号下(1-cos^2 10°)
化简根号下(1-2sin10°cos10°)/[cos10°-根号下(1-sin^2 80°)]