10x+12(108-x)=1142
解方程.(5x/x²+x-6)+(2x-5/x²-x-12)=7x-10/x²-6x+8
(x+12)(x-2)+(x+7)(x+8)-(x+5)(x-10),其中x=2
X/15 + X/12 + X/10 = 1365,求X,
1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550
解方程x²+x-6分之5x+x²-x-12分之2x-5=x²-6x+8分之7x-10
解分式方程(5-2x)/(x^2-x-12)=5x/(x^2+x-6)+(10-7x)/(x^2-6x+8)得
一:已知f(x)=(10^x-10^-x)/10^x+10^-x.
(2x-2)(x-1)=0 x(x-5)=5x-10
(X-X*20%-18-(X-X*20%-18)*10%=X*1/2-3(过程)
12x-10x=3.6 x=?
12分之x+10=7X分之x+2
12/7x(x+10)=x+2