2x+y=2,x+2y=5,x-y+2z=-7
x/2=y/3=z/5 x+3y-z/x-3y+z
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai
x,y,z为实数 且(y-z)^2+(x-y)^2+(z-x)^2=(y+z-2x)^2+(x+z-2y)^2+(x+y
x,y,z为实数且(y-z)平方+(x-y)平方+(z-x)平方=(y+z-2x)平方+(z+x-2y)平方+(x+y-
(x+y-z)^2-(x-y+z)^2=?
2X+Y+Z=10,X+2Y+Z=-6,X+Y+2Z=8 5X+4Y-3Y=13,2X-3Y+7Z=19,3X-Y=2X
int x,y,z; x=2; y=4; z=7; x=y--
{5x-3y+z=2{5x+2y-4z=3{-5x+y-z=2 {x-y-z=-1{3x+5y+7z{4x-y+2x=-
分解因式:f(x,y,z)=x^2(y-z)+y^2(z-x)+z^2(x-y)
解方程组2x+y-z=7 x+y+z =1 2x-y-z=5
已知2x+5y+4z=6.3x+y-7z=-4 求 x+2y+z