sinx+√3cosx怎么等于2sin(x+π/3)
sinx+cosx/sinx-cosx=2 求sinx/cos^3x +cosx/sin^3x
已知函数f(x)=2cosx*sin(x+π/3)-√3sin^2x+sinx*cosx
已知(sinx+cosx)/(sinx-cosx)=3,求tanx,2sin²x+(sinx-cosx)&su
根号3/2*sinx+1/2*cosx 怎么变成sin(x+π/6)的呢
f(x)=cos(2x-π/3)+2sin(x-π/4)怎么化简成(sinx-cosx)(sinx+cosx)
已知函数f(x)=[2sin(x+π/3)+sinx]cosx-√3sin²x,x∈R
f(x)=2cos*sin(x+π/3)-^3sin^2x+sinx*cosx
已知sinx=2/3,求(cosx-sinx/cosx+sin)+(cosx+sin/cosx-sinx)的值.
已知函数f(x)=2cosx*sin(x+π/3)-根号3sin^2x+sinx*cosx
设f(x)=2cosx.sin(x+π/3)-根号3 sin平方x+sinx.cosx
已知函数f(x)=2cosx•sin(x+π3)+sinx•(cosx−3sinx)
已知sinx+cosx/sinx-cosx=3,求tanx,2sin^2x+(sinx-cosx)^2的值