M=m-n-1. N=2m-4n+3.
计算:1.[(m+n)(n-m)-(m+n)^2+3m(m+n)]除以(-2M),其中m=-4,n=2 2.(x+y)(
先化简,在求值(m+n)(m-n)(-m^2-n^2)-(-2m+n)(-2m-n)(4m^2+n^2) 其中m=1,n
n=m/M
已知3m=2n,则m/(m+n)+n/(m-n)-n^2/(m^2-n^2)=?
如果m和n互为相反数,则m+2m+3m+4m+5m+5n+4n+3n+2n+n=
如果m,n互为相反数,求m+2m+3m+4m+5m+5n+4n+3n+2n+n=多少
已知m/n=5、,求(m/(m+n))+(m/(m-n))-(n^2/(m^3-n^2))
[(m+n)(m-n)-(m-n)²+2n(m-n)]÷4n
若(m-2n)/(2m+n)=3,则[3(m-2n)/(2m+n)-(m-2n)/[2(2m+n)] - {9(m-2n
已知:m*m=n+2,n*n=m+2.求m*m*m-2mn+n*n*n(m不等于n).
已知2m+n分之m-2n=3,则2m+n分之3(m-2n)+3(2m+n)分之m-2n-4(2m+n)分之5(m-2n)
若m×m+n×n-6n+4m+13=0,则m×m-n×n=?